[備忘記]Java 如何製作亂數產生的密碼

public String makePassword(int passwordLength){
　//密碼的字符表(可以亂排，至於要不要有特殊字元就看後續的處理可否允許特殊字元的輸入)
　char[] word =
　　{'a','b','c','d','e','f',
　　'g','h','i','j','k','L',
　　'm','0','n','o','1','2',
　　'3','p','4','q','5','r',
　　's','6','t','7','u','v',
　　'8','w','x','9','y','z'};
　byte[] randomNumber = new byte[passwordLength];
　new Random().nextBytes(randomNumber);
　StringBuilder password = new StringBuilder();
　for(int i = 0; i < randomNumber.length; i++){
　　password.append(word[Math.abs(randomNumber[i]) % word.length]);
　}
　return password.toString();
}